Web9 aug. 2024 · 7sin2θ + 3cos2θ = 4 ⇒ 7sin2θ +3cos2θ = 4(sin2θ + cos2θ) ⇒ 7sin2θ +3cos2θ = 4sin2θ + 4cos2θ ⇒ 7sin2θ −4sin2θ = 4cos2θ − 3cos2θ ⇒ 3sin2θ = cos2θ ⇒ tan2θ = 1 … Web7sin 2 θ + 3cos 2 θ = 4. Formula used: sin 2 θ + cos 2 θ = 1 . Calculation: 7sin 2 θ + 3cos 2 θ = 4. ⇒ 4sin 2 θ + 3sin 2 θ + 3cos 2 θ = 4. ⇒ 4sin 2 θ + 3(sin 2 θ + cos 2 θ) = 4. ⇒ 4sin …
If ` 7 sin^(2) theta + 3 cos^(2) theta =4 , "then" sec theta + cosec ...
Web7 mrt. 2024 · Hint: Now to prove the given equation we will first write ${{\sin }^{6}}\theta ={{\left( {{\sin }^{2}}\theta \right)}^{3}}$ by using the law of indices ${{\left( {{a ... Web3cosθ+4sinθ = a sin (θ+α) you can convert this to sin (a+b) form sin (a+b) = sin (a)cos (b)+cos (a)sin (b) multiply and divide by 5 on left hand side for the given equation 5 ( 3 ∕ 5 … sifu redemption edition price
What is the value of a for 3 cos theta+ 4sin theta=a sin ... - Quora
WebStep 4. Set equal to and solve for . Tap for more steps... Set equal to . Solve for . Tap for more steps... Subtract from both sides of the equation. Divide each term in by and simplify. Tap for more steps... Divide each term in by . Simplify the left side. Tap for more steps... Cancel the common factor of . Web3 okt. 2024 · 1 answer 7 sin2 θ + 3 cos2 θ = 4 7 sin 2 θ + 3 cos 2 θ = 4, then find tan θ tan θ. asked in Trigonometry by Lohith01 (97.1k points) class-9 trigonometry 0 votes 1 answer … WebAnswer (1 of 11): Notice, 7\sin^2\theta+3\cos^2\theta=4 \frac{7\tan^2\theta}{\sec^2\theta}+\frac{3}{\sec^2\theta}=4 … the precast group