WebApr 5, 2024 · re.error: nothing to repeat at position 0 #461 Open mennatallah644 opened this issue on Apr 5, 2024 · 3 comments mennatallah644 commented on Apr 5, 2024 Sign up for free to join this conversation on GitHub . Already have an account? Sign in to comment Assignees No one assigned Labels None yet Projects None yet Milestone No milestone … WebOct 2, 2024 · The process quits with the line "re.error: nothing to repeat at position 2" in the Traceback. It seems to relate to the systems Python file "sre_parse.py" and the line 651: raise source.error("nothing to repeat", source.tell() - here + len(this))
Unexpected error: nothing to repeat at position 0" - PredictDB
WebJan 19, 2024 · The “Nothing to repeat at position 2” error is a regular expression error that occurs when a pattern in the regular expression has nothing to repeat. It means that there is a repetition operator (such as *, +, or ?) that is immediately following a character that cannot be repeated. Here are a few things you can try to resolve the issue: WebNov 15, 2024 · とやってみると re.error: nothing to repeat at position 0 というエラーが表示されてしまいます。 pythonで「?p」という文字列を検索するにはどうすればいいで … duplicate number checker
re.error: nothing to repeat at position 0 #461 - Github
WebFeb 13, 2012 · There is a repeated zero-width anchor is used in the Python re test suite, which is what made me notice this. I assume that came from some actual use-case. (see:... WebOct 16, 2024 · For this cause there is re.escape () function. This is the right code: re.search (re.escape ( '**myword' ), '/path/to/**myword' ) The problem here is that special character … WebAug 19, 2024 · 1 Answer Sorted by: 0 Looks like j contains some regular expression special character like *. If you want it to be interpreted as literal text, you can say pattern = r'\b'+re.escape (j)+r'\b' and possibly the same for r if it should similarly be coerced into a literal string. Share Improve this answer Follow answered Aug 19, 2024 at 5:47 tripleee duplicate object found in source - ignoring